the sum and product of the zeros of polynomial 9x^-5 repetitively are:​

2 thoughts on “the sum and product of the zeros of polynomial 9x^-5 repetitively are:​”

1. Answer:

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   answer will 0.

   \huge{Explanation}Explanation

   !—-Question—-!

   9x²-5

   !!—–Answer——!!

   9x²-5= 0

   9x²= 5

   x²= \bf\frac{5}{9}

   9

   5

   x= \bf\sqrt{\frac{5}{9}}

   9

   5

   or x = \bf-\sqrt{\frac{5}{9}}−

   9

   5

   so Addition of zeros

   \bf\sqrt{\frac{5}{9}}

   9

   5

   \bf-\sqrt{\frac{5}{9}}−

   9

   5

   = 0

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2. Answer:

   first answer is correct

   Reply