The slope of line joining the points (17,-13) and (17,8) is1 point10-1Not defined About the author Isabella
4th option Step-by-step explanation: Given:– The points (17,-13) and (17,8) To find:– Find the slope of line joining the points (17,-13) and (17,8) ? Solution:– Given points are (17,-13) and (17,8) Let (x1, y1)=(17,-13)=> x1=17 and y1=-13 Let (x2, y2)=(17,8)=>x2=17 and y2=8 We know that The slope of line segment joining the points (x1, y1) and (x2, y2) is (y2-y1)/(x2-x1) Slope of the line segment joining the given points => [8-(-13)]/(17-17) => (8+13)/0 => 21/0 => Not defined. Since division with zero is not defined. Alternative Method:– Given points (17,-13) and (17,8) are parallel to y-axis. The y-axis or any line parallel to the y-axis has no defined slope. Answer:– The slope of the line segment joining the given points is not defined . Used formulae:– The slope of line segment joining the points (x1, y1) and (x2, y2) is (y2-y1)/(x2-x1) The y-axis or any line parallel to the y-axis has no defined slope. The x-axis or any line parallel to the x-axis has slope is zero. Slope is denoted by m . Reply
4th option
Step-by-step explanation:
Given:–
The points (17,-13) and (17,8)
To find:–
Find the slope of line joining the points (17,-13) and (17,8) ?
Solution:–
Given points are (17,-13) and (17,8)
Let (x1, y1)=(17,-13)=> x1=17 and y1=-13
Let (x2, y2)=(17,8)=>x2=17 and y2=8
We know that
The slope of line segment joining the points
(x1, y1) and (x2, y2) is (y2-y1)/(x2-x1)
Slope of the line segment joining the given points
=> [8-(-13)]/(17-17)
=> (8+13)/0
=> 21/0
=> Not defined.
Since division with zero is not defined.
Alternative Method:–
Given points (17,-13) and (17,8) are parallel to y-axis.
The y-axis or any line parallel to the y-axis has no defined slope.
Answer:–
The slope of the line segment joining the given points is not defined .
Used formulae:–