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The sides of triangle are in ratio 3: 5:7 and its perimeter is 300 m find its area.
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By Allison

The sides of triangle are in ratio 3: 5:7 and its perimeter is 300 m find its area.
​

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Allison

If the
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Find the coordinates of the points which divide the line segment joining the points (3,-1) and (10, 13) internally in the ratio 2:

2 thoughts on “<br />The sides of triangle are in ratio 3: 5:7 and its perimeter is 300 m find its area.<br />​”

  2. Step-by-step explanation:

    Ratio of sides = 3:5:7

    Let sides be 3x, 5x, 7x

    So 3x + 5x + 7x = 300m

    15x = 300m

    x = 20 m

    Sides are 60m, 100m, 140m

    sLet coefficient of ratios be X.

    then,

    3x+5x+7x=300

    15x=300

    X=20

    Sides of triangle are :-

    60 m + 100 m + 140 m

    By Heron’s formula,

    We have,

    \begin{gathered}s = \frac{a + b + c}{2} \\ s = \frac{300}{2} \\ s = 150 \\ area = \sqrt{s(s – a)(s – b)(s – c)} \\ = \sqrt{150(150 – 60)(150 -100)(150 – 140)} \\ = \sqrt{150 \times 90 \times 50 \times 10} \\ = \sqrt{15 \times 9 \times 5 \times 10000} \\ = \sqrt{75 \times {3}^{2} \times {10}^{4} } \\ = \sqrt{75} \times 3 \times {10}^{2} \\ = \sqrt{75} \times 300 \\ = \sqrt{25 \times 3} \times 300 \\ = \sqrt{ {5}^{2} \times 3} \times 300 \\ = 1500 \times \sqrt{3} \\ = 1500 \sqrt{3} {m}^{2} \end{gathered}s=2a+b+cs=2300s=150area=s(s−a)(s−b)(s−c)=150(150−60)(150−100)(150−140)=150×90×50×10=15×9×5×10000=75×32×104=75×3×102=75×300=25×3×300=52×3×300=1500×3=15003m2

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