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The sides of a triangle are 50 cm, 78 cm and 112 cm. Find the length of the smallest
altitude.

By Cora

The sides of a triangle are 50 cm, 78 cm and 112 cm. Find the length of the smallest
altitude.

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Cora

If α and β are the roots of the equation x2-1 = 0, then show that α + β =1 + 1



?​

10
The total number of terms in the expression 8×2 + 2xy + 3×2 + 2y2
a) 3
(b) 2
(c) 5
(d) 4
​

1 thought on “The sides of a triangle are 50 cm, 78 cm and 112 cm. Find the length of the smallest <br /> altitude.”

  1. Answer:Using the formulas



    A=√s(s﹣a)(s﹣b)(s﹣c)

    s=a+b+c
    /2

    =√﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4
    /2b

    =√﹣504+2·(50·78)2+2·(50·112)2﹣784+2·(78·112)2﹣1124
    /2·78

    ≈43.07692cm

    Step-by-step explanation:

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