The radius of lens of curvature of a convex lens is 10 m The power of lens will be About the author Adalyn
Explanation: P= f 1 ⇒f= P 1 f= 10 1 m= 10 100cm =10cm Now f 1 =(μ−1)( R 1 1 − R 2 1 ) = 10 1 =(μ−1)( 10 1 −(− 10 1 )) ⇒ 10 1 =(μ−1) 10 2 ⇒μ−1= 2 1 ⇒μ=1+ 2 1 = 2 3 Reply
Answer: The radius of curvature of the plane surface of a Plano-convex lens is infinite. Let are the radius of curvature of the convex surface and plane surface of the planoconvex lens. The focal length of the lens [f] = 30 cm. P= f 1 ⇒f= P 1 f= 10 1 m= 10 100cm =10cm Now f 1 =(μ−1)( R 1 1 − R 2 1 ) = 10 1 =(μ−1)( 10 1 −(− 10 1 )) ⇒ 10 1 =(μ−1) 10 2 ⇒μ−1= 2 1 ⇒μ=1+ 2 1 = 2 3 Explanation: Reply
Explanation:
P=
f
1
⇒f=
P
1
f=
10
1
m=
10
100cm
=10cm
Now
f
1
=(μ−1)(
R
1
1
−
R
2
1
)
=
10
1
=(μ−1)(
10
1
−(−
10
1
))
⇒
10
1
=(μ−1)
10
2
⇒μ−1=
2
1
⇒μ=1+
2
1
=
2
3
Answer:
The radius of curvature of the plane surface of a Plano-convex lens is infinite.
Let are the radius of curvature of the convex surface and plane surface of the planoconvex lens. The focal length of the lens [f] = 30 cm.
P=
f
1
⇒f=
P
1
f=
10
1
m=
10
100cm
=10cm
Now
f
1
=(μ−1)(
R
1
1
−
R
2
1
)
=
10
1
=(μ−1)(
10
1
−(−
10
1
))
⇒
10
1
=(μ−1)
10
2
⇒μ−1=
2
1
⇒μ=1+
2
1
=
2
3
Explanation: