Answer: (-2.5 , 0) Step-by-step explanation: distances are equal from both the points so [tex]\sqrt{(x1-x)^{2}+(y1-y)^2 } = \sqrt{(x2-x)^{2}+(y2-y)^2 }[/tex] [tex]\sqrt{(5-x)^{2}+(-5-y)^2 } = \sqrt{(-2-x)^{2}+(9-y)^2 }[/tex] as the point is in the x-axis then y=0, so [tex]\sqrt{(5-x)^{2}+(-5)^2 } = \sqrt{(-2-x)^{2}+(9)^2 }[/tex] [tex]\ (5-x)^{2}+(-5)^2 } = \ (-2-x)^{2}+(9)^2 }[/tex] after solving this we get x = -2.5 so the final coordinate is (-2.5, 0). Reply
Answer:
(-2.5 , 0)
Step-by-step explanation:
distances are equal from both the points so
[tex]\sqrt{(x1-x)^{2}+(y1-y)^2 } = \sqrt{(x2-x)^{2}+(y2-y)^2 }[/tex]
[tex]\sqrt{(5-x)^{2}+(-5-y)^2 } = \sqrt{(-2-x)^{2}+(9-y)^2 }[/tex]
as the point is in the x-axis then y=0, so
[tex]\sqrt{(5-x)^{2}+(-5)^2 } = \sqrt{(-2-x)^{2}+(9)^2 }[/tex]
[tex]\ (5-x)^{2}+(-5)^2 } = \ (-2-x)^{2}+(9)^2 }[/tex]
after solving this we get
x = -2.5
so the final coordinate is (-2.5, 0).