The perimeter of a rectangle is 54cm. One side is 6cm longer than the other. Find the area of the rectangle About the author Eliza
Answer: let length be x and breadth be y first condition. x-y=6 second condition. 2(x+y)=54 x+y = 27 and solve hope it helps you Reply
Given :- Perimeter = 54 cm One side = 6 cm + Other side To find :- Area of rectangle = ? Solution :- Let one side be length = x. So the other side be breadth = y = (x + 6) cm Perimeter = 2 (l + b) ⇒ Perimeter = 2 (x + x + 6) ⇒ Perimeter = 2 (2x + 6) ⇒ Perimeter = 4x + 12 ⇒ 54 = 4x + 12 ⇒ 4x = 54 – 12 ⇒ 4x = 42 ⇒ x = 42 ÷ 4 ⇒ x = 10.5 cm For finding the value of y: y = x + 6 → y = 10.5 + 6 → y = 16.5 cm ∴ Length = 10.5 cm Breadth = 16.5 cm Area = Length × Breadth ⇒ Area = (10.5) (16.5) ⇒ Area = 173.25 Reply
Answer:
let length be x
and breadth be y
first condition.
x-y=6
second condition.
2(x+y)=54
x+y = 27
and solve
hope it helps you
Given :-
To find :-
Area of rectangle = ?
Solution :-
Let one side be length = x.
So the other side be breadth = y = (x + 6) cm
Perimeter = 2 (l + b)
⇒ Perimeter = 2 (x + x + 6)
⇒ Perimeter = 2 (2x + 6)
⇒ Perimeter = 4x + 12
⇒ 54 = 4x + 12
⇒ 4x = 54 – 12
⇒ 4x = 42
⇒ x = 42 ÷ 4
⇒ x = 10.5 cm
For finding the value of y:
y = x + 6
→ y = 10.5 + 6
→ y = 16.5 cm
∴ Length = 10.5 cm
Breadth = 16.5 cm
Area = Length × Breadth
⇒ Area = (10.5) (16.5)
⇒ Area = 173.25