the numerator of a fraction is 4 less that it’s denominator. if 1 is added to both its numerator and denominator, it becomes ⁴/¹². Fiund the fraction!! help please!!
2 thoughts on “the numerator of a fraction is 4 less that it’s denominator. if 1 is added to both its numerator and denominator, it becomes ⁴/¹².”
Question : –
The numerator of a fraction is 4 less than it’s denominator. If 1 is added to both it’s numerator and Denominator. Then, it becomes 4/12. Find the fraction.
_____________________________
★ Let the Denominator of the fraction be x respectively.
The numerator of a fraction is 4 less than it’s denominator. If 1 is added to both it’s numerator and Denominator. Then, it becomes 4/12. Find the fraction.
_____________________________
★ Let the Denominator of the fraction be x respectively.
According to the Question ⟹
If 1 is added to both it’s numerator and Denominator. Then, it becomes 4/12.
Question : –
The numerator of a fraction is 4 less than it’s denominator. If 1 is added to both it’s numerator and Denominator. Then, it becomes 4/12. Find the fraction.
_____________________________
★ Let the Denominator of the fraction be x respectively.
[tex]Then, \: it’s Numerator = (x \: – \: 4).[/tex]
[tex]According \: to \: the \: Question \rightarrow[/tex]
[tex]⟹ \: \frac{(x – 4) + 1}{x + 1} = \frac{4}{12} [/tex]
[tex]⟹ \: \frac{x – 3}{x + 1} = \frac{4}{12} [/tex]
[tex]⟹12(x – 3) = 4(x + 1)[/tex]
[tex]⟹12x – 36 = 4 x + 4[/tex]
[tex]⟹12x – 4x = 4 + 36[/tex]
[tex]⟹8x = 40[/tex]
[tex]⟹x = \frac{40}{8} [/tex]
[tex] \color{red}⟹x = 5[/tex]
so,
Numerator of fraction, (x – 4) = (5 – 4) = 1
Denominator of fraction, x = 5
★ hence the required fraction is 1/5...
Question : –
The numerator of a fraction is 4 less than it’s denominator. If 1 is added to both it’s numerator and Denominator. Then, it becomes 4/12. Find the fraction.
_____________________________
★ Let the Denominator of the fraction be x respectively.
According to the Question ⟹
If 1 is added to both it’s numerator and Denominator. Then, it becomes 4/12.
⟹ (x – 4) + 1 {x + 1} = 4/12
⟹ {x – 3} {x + 1} = 4/12
⟹12(x – 3) = 4(x + 1)
⟹12x – 36 = 4 x + 4
⟹12x – 4x = 4 + 36
⟹8x = 40
⟹x = 40/8
⟹x = 5
So ,
⟹ Numerator of fraction , (x – 4) = (5 – 4) = 1
⟹ Denominator of fraction , x = 5
★ Hence the required fraction is 1/5…