The numerator of a fraction is 3 less than it’s
denominator if we add to 1 to both the
numerator and denominator beco

1 thought on “The numerator of a fraction is 3 less than it’s <br />denominator if we add to 1 to both the <br />numerator and denominator beco”

1. Step-by-step explanation:

   Given, the numerator of a fraction is 3 less than the denominator

   Which means the fraction is (x-3)/x

   Now, we have added 1 to both numerator and denominator

   The new fraction is (x-3+1)/(x+1)

   >(x-2)/(x+1)

   Now both fractions are equal. Which means,

   (x-3)/x = (x-2)/(x+1)

   (x-3)(x+1) = x(x-2) [Because of cross multiplication]

   x² – 3x + x – 3 = x²-2x

   x² – 2x – 3 = x² – 2x

   -3 ≠ 0

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