The median and mode respectively of a frecuenc
distribution are 26 and 29. Then find its mean​

The median and mode respectively of a frecuenc
distribution are 26 and 29. Then find its mean​

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  1. [tex]\begin{gathered}\begin{gathered}\bf \:Given – \begin{cases} &\sf{Median = 26} \\ &\sf{Mode = 29} \end{cases}\end{gathered}\end{gathered}[/tex]

    [tex]\begin{gathered}\begin{gathered}\bf \:To\:find-\begin{cases} &\sf{Mean} \end{cases}\end{gathered}\end{gathered}[/tex]

    [tex]\large\underline{\sf{Solution-}}[/tex]

    Given that

    • Median = 26
    • Mode = 29

    We know that

    • Relationship between Mean, Mode and Median is given by Empirical Formula,

    • Empirical Formula is given by

    [tex]\rm :\longmapsto\:Mode = 3Median – 2Mean[/tex]

    On substituting the values of Median and Mode, we get

    [tex]\rm :\longmapsto\:29 = 3 \times 26 – 2Mean[/tex]

    [tex]\rm :\longmapsto\:29 = 78 – 2Mean[/tex]

    [tex]\rm :\longmapsto\:2Mean = 78 – 29[/tex]

    [tex]\rm :\longmapsto\:2Mean = 49[/tex]

    [tex]\bf\implies \:Mean = 24.5[/tex]

    Additional Information :-

    • The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set.
    • The median is the middle value when a data set is ordered from least to greatest.
    • The mode is the number that occurs most often in a data set.
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