The lines y=x and y=mx cross at the point P. What is the sum of the positive integer values of m for which the coordinates of P are also positive integers? ( If it helps,the options are :A-5B-7C-3D-10E-8 ) About the author Iris
Answer: I HOPE IT HELP YOU MARK ME AS BRAINLIST Step-by-step explanation: The number of integral values of m, for which the x-coordinate of the point of intersection of the lines 3x+4y=9 and y=mx+1 is also an integer, is A 2 B 0 C 4 D 1 Answer Open in answr app Correct option is A 2 By solving both equations for x coordinate, we get mx+1= 4 9−3x ⇒4mx+4=9−3x Or, 3x+4mx+4=9 Or, x=5/(3+4m) Since x has to be an integer, possible values of x are 5,−5,1,−1 for which, the denominator on R.H.S. has to be 1,−1,5,−5 respectively. Now, 3+4m=1,implies m=−0.5 3+4m=−1, implies m=−1 3+4m=5, implies m=0.5 3+4m=−5, implies m=−2. Hence, two integral values of m are possible. Reply
Answer:
I HOPE IT HELP YOU MARK ME AS BRAINLIST
Step-by-step explanation:
The number of integral values of m, for which the x-coordinate of the point of intersection of the lines 3x+4y=9 and y=mx+1 is also an integer, is
A
2
B
0
C
4
D
1
Answer
Open in answr app
Correct option is
A
2
By solving both equations for x coordinate, we get
mx+1=
4
9−3x
⇒4mx+4=9−3x
Or, 3x+4mx+4=9
Or, x=5/(3+4m)
Since x has to be an integer, possible values of x are 5,−5,1,−1 for which,
the denominator on R.H.S. has to be 1,−1,5,−5 respectively.
Now, 3+4m=1,implies m=−0.5
3+4m=−1, implies m=−1
3+4m=5, implies m=0.5
3+4m=−5, implies m=−2.
Hence, two integral values of m are possible.