The HCF of two numbers is 27and their LCM is 162. If one ofthe numbers is 54. what is theother number.O(1)36O(2)54O(3)9O(4)81 About the author Alaia
Answer: 6747_588585588585858585858545775547533524243546576896970u97968675633542245364t7uopioyit6rte6r57yiouuo453553535647586868686756464354231314252537475 Reply
Answer: 81 Step-by-step explanation: for two numbers a and b, we know that (a×b)= HCF of (a,b)×LCM of (a,b) here, a = 54,HCF = 27, LCM = 162 Therefore, (54×b) = (27×162) b= 27×162/54 =81 hence, the other no. is 81 Reply
Answer:
6747_588585588585858585858545775547533524243546576896970u97968675633542245364t7uopioyit6rte6r57yiouuo453553535647586868686756464354231314252537475
Answer:
81
Step-by-step explanation:
for two numbers a and b, we know that
(a×b)= HCF of (a,b)×LCM of (a,b)
here,
a = 54,HCF = 27, LCM = 162
Therefore,
(54×b) = (27×162)
b= 27×162/54
=81
hence, the other no. is 81