The HCF and LCM of two numbers is 5 and 30 respectively. If one of the numbers is 10, find the other number.

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1. [tex] \underline \mathfrak \red{Question-:}[/tex]

   • The HCF and LCM of two numbers is 5 and 30 respectively. If one of the numbers is 10, find the other number.

   [tex] \underline \mathfrak \red{Answer-:}[/tex]

   FORMULA REQUIRED –:

   Product of 2 numbers = LCM × HCF

   [tex] \underline \mathfrak \pink{Given-:}[/tex]

   LCM = 5

   HCF = 30

   FIRST NUMBER = 10

   OTHER NUMBER = ?

   Therefore , other number =

   [tex] \red{→5 \times \frac{30}{10}}[/tex]

   [tex] \red{→ \frac{150}{10}}[/tex]

   [tex] \red{ = 15}[/tex]

   Hence , The other number is 15 !

   ( ☘Apologies for any mistakes made in the above answer)

   ( ☘Not a copied answer ᕕ( ᐛ )ᕗ)

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