the first term of a geometric progression is 81 and the common ratio is 2/6. the product of the first 10 terms is About the author Cora
Given : the first term of a geometric progression is 81 and the common ratio is 2/6. To Find : the product of the first 10 terms Solution: First term a = 81 r = common ratio = 2/6 = 1/3 nth term = arⁿ⁻¹ GP 10 terms a , ar , ar² , _____ , ar⁹ Product = a¹⁰r¹⁺²⁺³ … ⁺⁸⁺⁹ 1 + 2 + 3 + .. + 8 + 9 = 9 (10)2 = 45 Product = a¹⁰r⁴⁵ a = 81 = 3⁴ r = 1/3 = (3⁴)¹⁰(1/3)⁴⁵ = 3⁴⁰/3⁴⁵ = 1/3⁵ = 1/243 Product of the first 10 terms is 1/243 Learn More: The pth,2pth and 4pth terms of an ap are in gp then the common … brainly.in/question/13332271 the product of 4 numbers in GP is 64 the ratio of the sum of the … brainly.in/question/12357635 23. A geometric progression (GP) consistsof 200 terms. If the sum of … brainly.in/question/13730835 Reply
Given : the first term of a geometric progression is 81 and the common ratio is 2/6.
To Find : the product of the first 10 terms
Solution:
First term a = 81
r = common ratio = 2/6 = 1/3
nth term = arⁿ⁻¹
GP 10 terms
a , ar , ar² , _____ , ar⁹
Product = a¹⁰r¹⁺²⁺³ … ⁺⁸⁺⁹
1 + 2 + 3 + .. + 8 + 9 = 9 (10)2 = 45
Product = a¹⁰r⁴⁵
a = 81 = 3⁴
r = 1/3
= (3⁴)¹⁰(1/3)⁴⁵
= 3⁴⁰/3⁴⁵
= 1/3⁵
= 1/243
Product of the first 10 terms is 1/243
Learn More:
The pth,2pth and 4pth terms of an ap are in gp then the common …
brainly.in/question/13332271
the product of 4 numbers in GP is 64 the ratio of the sum of the …
brainly.in/question/12357635
23. A geometric progression (GP) consistsof 200 terms. If the sum of …
brainly.in/question/13730835
Answer:
5
Step-by-step explanation:
5