Answer: (x1,y1) = (2,-3) m = (2+3)/(-1-2) m = – 5/3 (y-y1) = m(x-x1) (y + 3) = -5/3 (x – 2) y + 3 = -5/3 x + 10/3 5/3 x + y + 3-10/3 = 0 5/3 x + y – 1/3 = 0 Reply
Answer:
(x1,y1) = (2,-3)
m = (2+3)/(-1-2)
m = – 5/3
(y-y1) = m(x-x1)
(y + 3) = -5/3 (x – 2)
y + 3 = -5/3 x + 10/3
5/3 x + y + 3-10/3 = 0
5/3 x + y – 1/3 = 0