The energy difference of two states of an atom is 8.1 keV. Determine the wavelength of
he light emitted or absorbed when an e

The energy difference of two states of an atom is 8.1 keV. Determine the wavelength of
he light emitted or absorbed when an electron jumps between these two states.​

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  1. Explanation:

    As we know,

    1/λ=R(1/n

    1

    2

    −1/n

    2

    2

    )

    =R(1/3

    2

    −1/4

    2

    )

    λ=1.875 ×10

    −6

    m

    ΔE=hc/λ = 1.06×10

    −19

    Reply

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