the dimensions of a room are 8m, 6m and 5 metre. find the cost of distempering it’s for walls at the rate of ₹80 per square metre. About the author Kinsley
Given : Dimensions of a room are 8 m, 6 m and 5 m. To Find : Cost of distempering it’s four walls at the rate of Rs. 80 per metre square. Calculations : Given that, Dimensions of a room are 8 m, 6 m and 5 m. Supposition: Let us suppose the dimensions of a room as, Length of the room = 8 m Breadth of the room = 6 m Height of the room = 5 m So, firstly let’s calculate the area of four walls in order to calculate the amount [cost] of distempering it’s four walls. ~ Calculating the area of four walls, For this, we need to use this formula :- 2 × (l + b) × h Where, l = length = 8 m b = breadth = 6 m h = height = 5 m Now, putting the values, ⇒ 2 × (l + b) × h ⇒ 2 × (8 + 6 m) × 5 m ⇒ 2 × 14 m × 5 m ⇒ 2 × (14 m × 5 m) ⇒ 2 × 70 m² ⇒ 140 m² Hence, The area of four walls is 140 m². According to the Question, Now let us calculate the cost of distempering it’s four walls at the rate of Rs. 80 per metre square. For finding the amount of distempering the four walls, we need to perform multiplication in :- Rate of rupees (Rs. 80) × Area of four walls (140 m²) ⇒ Rs. 80 × 140 m² ⇒ Rs. 11200 Henceforth, Cost of distempering it’s four walls at the rate of Rs. 80 per metre square is Rs. 11200. [tex] [/tex] Reply
Given : Length of the room = 8 m Breadth of the room = 6 m Height of the room = 5 m Rate of ditempering the wall = ₹ 80 To find : Cost of distempering it’s four walls at the rate of ₹ 80 Concept Used : → Formula to calculate area of four walls :- Area of four walls = 2(l + b) × h where, l = length b = breadth h = height To find the cost of distempering it’s four walls :- Firstly, find the area of the four walls. Then multiply the area of four walls by the rate of distempering the resultant value will be the required answer. Let’s do it. → ⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━ Solution : Area of four walls :- ⠀⠀⠀⇒ Area = 2(l + b) × h ⠀⠀⠀⇒ Area = 2(8 + 6) × 5 ⠀⠀⠀⇒ Area = 2(14) × 5 ⠀⠀⠀⇒ Area = 28 × 5 ⠀⠀⠀⇒ Area = 140 Area of four walls = 140 m² Cost of distempering the four walls = Area of four walls × Rate ⠀⠀⠀⇒ Cost = 140 × 80 ⠀⠀⠀⇒ Cost = 11,200 Cost of distempering it’s four walls at the rate of ₹ 80 = Rs. 11,200 ⠀⠀⠀━━━━━━━━━━━━━━━ Know MorE : Some related formulae :- Area of rectangle = l × b Area of square = side × side Total surface area of cube = 6 × side² Total surface Area of cuboid = 2(lb + bh + hl) Perimeter of square = 4 × side Perimeter of reactangle = 2(l + b) Perimeter of cuboid = 4 (length + breadth + height) Perimeter of cube = 12 × side Diagonal of square = √2a Diagonal of rectangle = √l² + √b² Volume of cuboid = length × breadth × height Volume of cube = side³ Reply
Given :
To Find :
Calculations :
Given that,
Supposition:
Let us suppose the dimensions of a room as,
So, firstly let’s calculate the area of four walls in order to calculate the amount [cost] of distempering it’s four walls.
~ Calculating the area of four walls,
For this, we need to use this formula :-
Where,
Now, putting the values,
⇒ 2 × (l + b) × h
⇒ 2 × (8 + 6 m) × 5 m
⇒ 2 × 14 m × 5 m
⇒ 2 × (14 m × 5 m)
⇒ 2 × 70 m²
⇒ 140 m²
Hence,
According to the Question,
Now let us calculate the cost of distempering it’s four walls at the rate of Rs. 80 per metre square.
For finding the amount of distempering the four walls, we need to perform multiplication in :-
⇒ Rs. 80 × 140 m²
⇒ Rs. 11200
Henceforth,
[tex] [/tex]
Given :
To find :
Concept Used :
→ Formula to calculate area of four walls :-
where,
To find the cost of distempering it’s four walls :-
Let’s do it. →
⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━
Solution :
Area of four walls :-
⠀⠀⠀⇒ Area = 2(l + b) × h
⠀⠀⠀⇒ Area = 2(8 + 6) × 5
⠀⠀⠀⇒ Area = 2(14) × 5
⠀⠀⠀⇒ Area = 28 × 5
⠀⠀⠀⇒ Area = 140
Area of four walls = 140 m²
Cost of distempering the four walls = Area of four walls × Rate
⠀⠀⠀⇒ Cost = 140 × 80
⠀⠀⠀⇒ Cost = 11,200
Cost of distempering it’s four walls at the rate of ₹ 80 = Rs. 11,200
⠀⠀⠀━━━━━━━━━━━━━━━
Know MorE :
Some related formulae :-