the curved surface area of a right circular cylinder of height 14 cm is 88 cm2. find the diameter of the base of the cylinder About the author Lydia
Given : Height of Cylinder = 14cm Curved Surface Area of Cylinder = 88cm² Find : Diameter of the Base of the Cylinder. [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex] [tex]{ }[/tex] ★ Now, first we find Curved Surface Area : [tex]{ }[/tex] [tex]\sf{\blue{Curved\:Surface\:Area\:=\:2 \pi rh}}[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{2 \pi rh\:=\:88cm}^{2}}[/tex] [tex]{ }[/tex] [tex]\:\:\dashrightarrow\:\sf{2\:\times\:{\dfrac{22}{7}}\:\times\:r\:\times\:14cm\:=\:88}[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{r\:=\:{\dfrac{88\:\times\:7}{2\:\times\:22\:\times\:14}}}}[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:\:\:\:\:\dashrightarrow{\sf{r\:=\:1cm}}[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex] [tex]{ }[/tex] ★ Now, we find the Diameter of the base of the cylinder. [tex]{ }[/tex] [tex]\sf{\blue{Diameter\:=\:2\:\times\:radius}}[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{2\:\times\:1}}[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{2}}[/tex] [tex]{ }[/tex] [tex]\:\therefore\:{\underline{\sf{Hence, \:the\:Diameter\: of\:the\: base\: of \:the \:cylinder\:is\:{\textsf{\textbf{ 2\:cm}}}}}}.[/tex] [tex]{ }[/tex] [tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex] Reply
Answer : Diameter of the base of the cylinder is 2cm Given : The curved surface area of a right circular cylinder of height 14cm is 88cm² To find : The diameter of the base of the cylinder Solution : Let the diameter of the base of the cylinder be r Height is 14cm Curved surface area of a right circular cylinder is 88cm² As we know that, Curved surface area of cylinder = 2πrh 》Curved surface area of cylinder = 2πrh 》88 = 2πrh 》88 = 2 × 22/7 × r × 14 》r = 88 × 7 / 2 × 22 × 14 》r = 1cm Radius is 1cm Now , we have to find the Diameter of the base of the cylinder: We know that, Diameter = 2 × r 》Diameter = 2 × r 》2 × 1 》2cm Hence,Diameter of the base of the cylinder is 2cm Reply
Given :
Find : Diameter of the Base of the Cylinder.
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[tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex]
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★ Now, first we find Curved Surface Area :
[tex]{ }[/tex]
[tex]{ }[/tex]
[tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{2 \pi rh\:=\:88cm}^{2}}[/tex]
[tex]{ }[/tex]
[tex]\:\:\dashrightarrow\:\sf{2\:\times\:{\dfrac{22}{7}}\:\times\:r\:\times\:14cm\:=\:88}[/tex]
[tex]{ }[/tex]
[tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{r\:=\:{\dfrac{88\:\times\:7}{2\:\times\:22\:\times\:14}}}}[/tex]
[tex]{ }[/tex]
[tex]\:\:\:\:\:\:\:\:\:\:\:\:\dashrightarrow{\sf{r\:=\:1cm}}[/tex]
[tex]{ }[/tex]
[tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex]
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★ Now, we find the Diameter of the base of the cylinder.
[tex]{ }[/tex]
[tex]{ }[/tex]
[tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{2\:\times\:1}}[/tex]
[tex]{ }[/tex]
[tex]\:\:\:\:\:\:\:\:\dashrightarrow\:{\sf{2}}[/tex]
[tex]{ }[/tex]
[tex]\:\therefore\:{\underline{\sf{Hence, \:the\:Diameter\: of\:the\: base\: of \:the \:cylinder\:is\:{\textsf{\textbf{ 2\:cm}}}}}}.[/tex]
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[tex]\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━[/tex]
Answer :
Given :
To find :
Solution :
As we know that,
》Curved surface area of cylinder = 2πrh
》88 = 2πrh
》88 = 2 × 22/7 × r × 14
》r = 88 × 7 / 2 × 22 × 14
》r = 1cm
Radius is 1cm
Now , we have to find the Diameter of the base of the cylinder:
We know that,
》Diameter = 2 × r
》2 × 1
》2cm
Hence,Diameter of the base of the cylinder is 2cm