The curvature of the curve y = f (x) is zero at every point on the curve. Which one of the following

could be f (x)?​

2 thoughts on “The curvature of the curve y = f (x) is zero at every point on the curve. Which one of the following<br /><br />could be f (x)?​”

1. Answer:

   mrnrmtkrmen

   Step-by-step explanation:

   नजर में ट् रो रहा था और एक अँ धे श क् ष क र ति क र ka kya ho gya tha ki baat kr rha tha

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2. Step-by-step explanation:

   Step-by-step explanation:

   \begin{gathered}\implies \sf{\dfrac{10x+3y}{5x+2y} = \dfrac{9}{5} }\\\\\\\implies \sf{\dfrac{10x\frac{y}{y} +3y}{5x\frac{y}{y}+2y}=\dfrac{9}{5} }\\\\\\\implies \sf{\dfrac{y\big(10\frac{x}{y}+3\big)}{y\big(5\frac{x}{y}+2\big)}=\dfrac{9}{5} }\end{gathered}

   ⟹

   5x+2y

   10x+3y

   =

   5

   9

   ⟹

   5x

   y

   y

   +2y

   10x

   y

   y

   +3y

   =

   5

   9

   ⟹

   y(5

   y

   x

   +2)

   y(10

   y

   x

   +3)

   =

   5

   9

   Let \dfrac{x}{y}=k

   y

   x

   =k ,

   \begin{gathered}\implies\sf{\dfrac{10k+3}{5k+2}=\dfrac{9}{5}} \\\\\implies\sf{5(10k+3)=9(5k+2) }\\\\\implies\sf{k=\dfrac{3}{5}}\end{gathered}

   ⟹

   5k+2

   10k+3

   =

   5

   9

   ⟹5(10k+3)=9(5k+2)

   ⟹k=

   5

   3

   Hence,

   \begin{gathered}\implies \sf{\dfrac{2x+y}{x+2y} }\\\\\\\implies \sf{\dfrac{2x\frac{y}{y} +y}{x\frac{y}{y}+2y} }\\\\\\\implies \sf{\dfrac{y\big(2\frac{x}{y}+1\big)}{y\big(\frac{x}{y}+2\big)} }\end{gathered}

   ⟹

   x+2y

   2x+y

   ⟹

   x

   y

   y

   +2y

   2x

   y

   y

   +y

   ⟹

   y(

   y

   x

   +2)

   y(2

   y

   x

   +1)

   \begin{gathered}\implies\sf{\dfrac{2k+1}{k+2} =\dfrac{2\big(\frac{3}{5}\big)+1}{\frac{3}{5}+2} }\\\\\implies\sf{ \dfrac{11}{13} }\end{gathered}

   ⟹

   k+2

   2k+1

   =

   5

   3

   +2

   2(

   5

   3

   )+1

   ⟹

   13

   11

   Question 2:

   Let the x should be added,

   ⇒ (2 + x)/(5 + x) = 6/11

   ⇒ 11(2 + x) = 6(5 + x)

   ⇒ 22 + 11x = 30 + 6x

   ⇒ 11x – 6x = 30 – 22

   ⇒ 5x = 8

   ⇒ x = 8/5

   8/5 should be subtracted

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