2 thoughts on “The combined equation of the two lines passing through the origin angle 45° & 135° with the positive x axis is”
Answer:
Solution:
The auxiliary equation of the lines given by ax2 + 2hxy + by2 = 0 is bm2 + 2hm + a = 0. Since one of the lines bisects an angle between the coordinate axes, that line makes an angle of 45° or 135° with the positive direction of X-axis.
Answer:
Solution:
The auxiliary equation of the lines given by ax2 + 2hxy + by2 = 0 is bm2 + 2hm + a = 0. Since one of the lines bisects an angle between the coordinate axes, that line makes an angle of 45° or 135° with the positive direction of X-axis.
Explanation:
Line passes through the point (1,5).
It makes angle 135°with x-axis. Therefore,
Slope, m = tan135° =−1
Equation of line is
y−y 1 =m(x−x 1)y−5=−1(x−1)y−5=−x+1x+y−6=0
Hence, x+y-6=0 is correct.
Answer:
The combined equation of the two lines passing through the origin angle 45° & 135° with the positive x axis is X² – Y² = 0