the base of an isosceles triangle is 4/3cm . The perimeter of the triangle is 4:2/15cm . what is the length of either of the remaining equal sides. About the author Alaia
Step-by-step explanation: Solution : Let any of the remaining side of the isosceles triangle is x cm in length. Then, Perimeter of triangle, =x+x+43=2x+43 cm ⇒2x+43=4215( Perimeter is 4215) ⇒2x+43=6215⇒2x=6215−43 ⇒2x=4215⇒x=1410=75=125 cm So, Required sides of given triangles are 125 cm each Reply
Answer:
I don’t know answer sorry
Step-by-step explanation:
Solution :
Let any of the remaining side of the isosceles triangle is x cm in length. Then,
Perimeter of triangle, =x+x+43=2x+43 cm
⇒2x+43=4215( Perimeter is 4215)
⇒2x+43=6215⇒2x=6215−43
⇒2x=4215⇒x=1410=75=125 cm
So, Required sides of given triangles are 125 cm each