the base of a prism is an equlateral triangle of perimetre 21 centimetres and its height 6 cm what is its total surface area About the author Hadley
Answer: Given: the base is a right angled triangle with sides a=6cm, b=8cm, c=10cm and T.S.A=156cm 2 . We know that T.S.A.=2B+Ph=2× 2 1 ×8×6+(6+8+10)h=48+24h. Thus 48+24h=156. This implies that 24h=156−48=108. Hence h= 24 108 =4.5cm. Therefore LSA=Ph=(6+8+10)×4.5=24×4.5=108cm 2 . Reply
Step-by-step explanation: the base of a prism is an equlateral triangle of perimetre 21 centimetres and its height 6 cm what is its total surface area Reply
Answer:
Given: the base is a right angled triangle with sides a=6cm, b=8cm, c=10cm and T.S.A=156cm
2
. We know that
T.S.A.=2B+Ph=2×
2
1
×8×6+(6+8+10)h=48+24h.
Thus 48+24h=156. This implies that 24h=156−48=108.
Hence h=
24
108
=4.5cm.
Therefore LSA=Ph=(6+8+10)×4.5=24×4.5=108cm
2
.
Step-by-step explanation:
the base of a prism is an equlateral triangle of perimetre 21 centimetres and its height 6 cm what is its total surface area