The average number of phone 1 pointcalls per minute in a call centreis 4. Find the probability thatduring a specific minute, thenumber of calls is less than 2.(Given : e^(-4) = 0.0183)O a) 0.0732O b) 0.1464O c) 0.9085O d) 0.0915 About the author Brielle
Answer: 0.0915 Step-by-step explanation: p = (e^(-r))(r)^x ————— x! x=no of success in the question r=mean of success for no of calls =1 p1 = (e^(-4))(4)^1 —————- = 4 * (0.0183) 1! for no of calls =0 p0 = (e^(-4))(4)^0 —————– = 1 * (0.0183) 0! as per the question required probability = p0 + p1 = [4*(0.0183)]+[1*(0.0183)] =0.0915 Reply
Answer:
0.0915
Step-by-step explanation:
p = (e^(-r))(r)^x
—————
x!
x=no of success in the question
r=mean of success
for no of calls =1
p1 = (e^(-4))(4)^1
—————- = 4 * (0.0183)
1!
for no of calls =0
p0 = (e^(-4))(4)^0
—————– = 1 * (0.0183)
0!
as per the question
required probability = p0 + p1
= [4*(0.0183)]+[1*(0.0183)]
=0.0915