The area of the four walls of a room is 300m^2. Its length and height are 15 m and 6 m respectively. find its breadth​

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The area of the four walls of a room is 300m^2. Its length and height are 15 m and 6 m respectively. find its breadth​

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  1. [tex]\begin{gathered}\begin{gathered}\bf\: Given-\begin{cases} &\sf{Area_{(4 walls)} = 300 \: {m}^{2} } \\ &\sf{Length, \: l \: = 15 \: m}\\ &\sf{Height, \: h \: = 6 \: m} \end{cases}\end{gathered}\end{gathered}[/tex]

    [tex]\begin{gathered}\begin{gathered}\bf \: To \: Find – \begin{cases} &\sf{Breadth, \: b}\end{cases}\end{gathered}\end{gathered}[/tex]

    [tex]\begin{gathered}\Large{\bold{{\underline{Formula \: Used – }}}} \end{gathered}[/tex]

    [tex] \boxed{ \red{ \sf \:Area_{(4 walls)} = 2(l + b) \times h}}[/tex]

    where,

    • l = Length
    • b = Breadth
    • h = Height

    [tex]\large\underline{\sf{Solution-}}[/tex]

    ↝ Given that

    • Length = 15 m
    • Height = 6 m
    • Area of 4 walls = 300 square meter.

    ↝ We know that,

    [tex]\rm :\longmapsto\:Area_{(4 walls)} = 2(Length + Breadth) \times Height[/tex]

    ↝ On substituting the values, we get

    [tex]\rm :\longmapsto\:300 = 2(15 + b) \times 6[/tex]

    [tex]\rm :\longmapsto\:25 = 15 + b[/tex]

    [tex]\rm :\longmapsto\:b = 10 \: m[/tex]

    [tex]\bf\implies \:Breadth, \: b \: = \: 10 \: m[/tex]

    Additional Information :-

    ↝ Cube:

    • A cube has six faces, eight vertices and twelve edges. All the faces of the cube are in square shape and are of equal length.

    ↝ Cuboid:

    • A cuboid has six faces, eight vertices and twelve edges. The faces of the cuboid are parallel. But not all the faces of a cuboid are equal in length.

    ↝ Formula’s of Cube :-

    • Total Surface Area = 6(side)²
    • Curved Surface Area = 4(side)²
    • Volume of Cube = (side)³
    • Diagonal of a cube = √3(side)
    • Perimeter of cube = 12 x side

    ↝ Formula’s of Cuboid

    • Total Surface area = 2 (Length x Breadth + breadth x height + Length x height)
    • Curved Surface area = 2 height(length + breadth)
    • Volume of the cuboid = (length × breadth × height)
    • Diagonal of the cuboid =√(l² + b² + h²)
    • Perimeter of cuboid = 4 (length + breadth + height)

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