The area of four walls of a room to be painted of sides 3cm, 5cm and 7cm is

a) 142cm2

b) 105cm2 c) 112 cm2
By Rose

The area of four walls of a room to be painted of sides 3cm, 5cm and 7cm is

a) 142cm2

b) 105cm2 c) 112 cm2

d) 30 cm2​

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Rose

2 thoughts on “The area of four walls of a room to be painted of sides 3cm, 5cm and 7cm is<br /><br />a) 142cm2<br /><br />b) 105cm2 c) 112 cm2<b”

  1. Answer :

    • Area of four walls of a room to be painted is 112cm²
    • (c) Option

    Given :

    • The area of four walls of a room to be painted of sides 3cm , 5cm and 7cm

    To find :

    • Area of four walls of a room to be painted

    Solution :

    Given ,

    • Length = 3cm
    • Breadth = 5cm
    • Height = 7cm

    So , room is like a cuboid then ,

    As we know that,

    • Lateral surface area of cuboid = 2h(l + b)

    where, l is length 3cm , b is breadth 5cm and h is height 7cm

    》 2h(l + b)

    》2 × 7 (3 + 5)

    》14(8)

    》112cm²

    Hence , Area of four walls of a room to be painted is 112cm²

    More Explanation:

    • Volume of cuboid = lbh
    • Total surface area of cuboid = 2(lb + bh + lh)
    • Perimeter of cuboid = 4(l + b + h)
    • where, l is length , b is breadth and h is height
    Reply
  2. [tex] \huge{ \mathfrak{ \color{navy}{Question:- }}}[/tex]

    • The area of four walls of a room to be painted of sides 3cm, 5cm and 7cm is

    a) 142cm²

    b) 105cm²

    c) 112 cm²

    d) 30 cm2²

    [tex] \huge{ \color{green}{ \mathfrak{Given:-}}}[/tex]

    • Length =3 cm
    • Breadth = 5cm
    • Height = 7cm

    [tex] \huge{ \mathfrak{ \color{pink}{To \: find:-}}}[/tex]

    • The area of four walls of a room to be painted

    [tex] \huge{ \mathfrak{ \color{brown}{Answer:-}}}[/tex]

    • [tex] \large \sf \: 112m²[/tex]

    [tex] \huge{ \mathfrak{ \color{gold}{Step \: by \: step \: Solution:- }}}[/tex]

    [tex] \\ \: \: \: \: \: \: \: \: \: \: \implies \: \boxed{ \underline{ \sf{ \red{Area \: of \: four \: walls = 2h(l + b)}}}}[/tex]

    [tex] \\ \: \: \: \: \: \: \: \implies{ \boxed{ \sf 2 \times 7(3 + 5)}} {m}^{2} [/tex]

    [tex] \\ \: \: \: \: \: \: \: \red \longmapsto \: 14 \times 8 {m}^{2} [/tex]

    [tex] \\ \: \: \: \: \: \: \: \: \pink \longmapsto \: 112 {m}^{2} [/tex]

    [tex] \boxed{ \underline{ \sf{ \pink{Therefore \: the \: area \: of \: four \: walls \: of \: a \: room \: to \: be \: painted \: is \:{ \boxed{ \red{ \mathfrak{112m²}}}}}}}}[/tex]

    [tex] { \blue{━━━━━━━━━━━━━━━━━━━━━━━━━━━━━}}[/tex]

    Reply

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