The area of four walls of a room to be painted of sides 3cm, 5cm and 7cm is a) 142cm2 b) 105cm2 c) 112 cm2 d) 30 cm2 About the author Rose
Answer : Area of four walls of a room to be painted is 112cm² (c) Option Given : The area of four walls of a room to be painted of sides 3cm , 5cm and 7cm To find : Area of four walls of a room to be painted Solution : Given , Length = 3cm Breadth = 5cm Height = 7cm So , room is like a cuboid then , As we know that, Lateral surface area of cuboid = 2h(l + b) where, l is length 3cm , b is breadth 5cm and h is height 7cm 》 2h(l + b) 》2 × 7 (3 + 5) 》14(8) 》112cm² Hence , Area of four walls of a room to be painted is 112cm² More Explanation: Volume of cuboid = lbh Total surface area of cuboid = 2(lb + bh + lh) Perimeter of cuboid = 4(l + b + h) where, l is length , b is breadth and h is height Reply
[tex] \huge{ \mathfrak{ \color{navy}{Question:- }}}[/tex] The area of four walls of a room to be painted of sides 3cm, 5cm and 7cm is a) 142cm² b) 105cm² c) 112 cm² d) 30 cm2² [tex] \huge{ \color{green}{ \mathfrak{Given:-}}}[/tex] Length =3 cm Breadth = 5cm Height = 7cm [tex] \huge{ \mathfrak{ \color{pink}{To \: find:-}}}[/tex] The area of four walls of a room to be painted [tex] \huge{ \mathfrak{ \color{brown}{Answer:-}}}[/tex] [tex] \large \sf \: 112m²[/tex] [tex] \huge{ \mathfrak{ \color{gold}{Step \: by \: step \: Solution:- }}}[/tex] [tex] \\ \: \: \: \: \: \: \: \: \: \: \implies \: \boxed{ \underline{ \sf{ \red{Area \: of \: four \: walls = 2h(l + b)}}}}[/tex] [tex] \\ \: \: \: \: \: \: \: \implies{ \boxed{ \sf 2 \times 7(3 + 5)}} {m}^{2} [/tex] [tex] \\ \: \: \: \: \: \: \: \red \longmapsto \: 14 \times 8 {m}^{2} [/tex] [tex] \\ \: \: \: \: \: \: \: \: \pink \longmapsto \: 112 {m}^{2} [/tex] [tex] \boxed{ \underline{ \sf{ \pink{Therefore \: the \: area \: of \: four \: walls \: of \: a \: room \: to \: be \: painted \: is \:{ \boxed{ \red{ \mathfrak{112m²}}}}}}}}[/tex] [tex] { \blue{━━━━━━━━━━━━━━━━━━━━━━━━━━━━━}}[/tex] Reply
Answer :
Given :
To find :
Solution :
Given ,
So , room is like a cuboid then ,
As we know that,
where, l is length 3cm , b is breadth 5cm and h is height 7cm
》 2h(l + b)
》2 × 7 (3 + 5)
》14(8)
》112cm²
Hence , Area of four walls of a room to be painted is 112cm²
More Explanation:
[tex] \huge{ \mathfrak{ \color{navy}{Question:- }}}[/tex]
a) 142cm²
b) 105cm²
c) 112 cm²
d) 30 cm2²
[tex] \huge{ \color{green}{ \mathfrak{Given:-}}}[/tex]
[tex] \huge{ \mathfrak{ \color{pink}{To \: find:-}}}[/tex]
[tex] \huge{ \mathfrak{ \color{brown}{Answer:-}}}[/tex]
[tex] \huge{ \mathfrak{ \color{gold}{Step \: by \: step \: Solution:- }}}[/tex]
[tex] \\ \: \: \: \: \: \: \: \: \: \: \implies \: \boxed{ \underline{ \sf{ \red{Area \: of \: four \: walls = 2h(l + b)}}}}[/tex]
[tex] \\ \: \: \: \: \: \: \: \implies{ \boxed{ \sf 2 \times 7(3 + 5)}} {m}^{2} [/tex]
[tex] \\ \: \: \: \: \: \: \: \red \longmapsto \: 14 \times 8 {m}^{2} [/tex]
[tex] \\ \: \: \: \: \: \: \: \: \pink \longmapsto \: 112 {m}^{2} [/tex]
[tex] \boxed{ \underline{ \sf{ \pink{Therefore \: the \: area \: of \: four \: walls \: of \: a \: room \: to \: be \: painted \: is \:{ \boxed{ \red{ \mathfrak{112m²}}}}}}}}[/tex]
[tex] { \blue{━━━━━━━━━━━━━━━━━━━━━━━━━━━━━}}[/tex]