the area of four walls of a room is 960sq .m.if the length of the room is thrice its breadth and height is 8m,find the area of the floor About the author Peyton
Answer: let breadth of room be y and length be 3y LSA of cuboid= 2(lh+bh) 960 = 2(3y×8+y×8) 960 = 2(24y+8y) 960 = 2(32y) 960 = 64y 960/64 = y 15 = y h = 8m b= 15m l=3y l=3×15 l= 45m area of floor= l×b =45×15 =675 m² Reply
Answer:
let breadth of room be y and length be 3y
LSA of cuboid= 2(lh+bh)
960 = 2(3y×8+y×8)
960 = 2(24y+8y)
960 = 2(32y)
960 = 64y
960/64 = y
15 = y
h = 8m
b= 15m
l=3y
l=3×15
l= 45m
area of floor= l×b
=45×15
=675 m²