The area of four walls of a room is 150 m2 . If the length of the room is twice its breadth an the height is 4 m, find the area of

2 thoughts on “The area of four walls of a room is 150 m2 . If the length of the room is twice its breadth an the height is 4 m, find the area of”

1. Answer:

   78.125 sq. m.

   Step-by-step explanation:

   Suppose the breadth is x.

   Then length = 2x

   [tex]lsa = 2h(l + b) \\ 150 = 2 \times 4(x + 2x) \\ 150 = 8 \times 3x \\ 150 = 24x \\ x = \frac{150}{24} = 6.25 \: m[/tex]

   Therefore the breadth of room = x = 6.25 m

   length of room = 2x = 12.5 m

   Area = length × breadth = 12.5 × 6.25 = 78.125 sq. m.

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2. Answer:–

   • 78.125 cm²

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   Step-by-step explaination:–

   Given:–

   • area of four walls = 150 m²

   • let breadth = b

   [tex]\\ [/tex]

   Length is twice its breadth

   • Therefore length = 2b

   • Height = 4 m

   [tex]\\ [/tex]

   Now curved surface area of cuboid = 2h(l+b)

   [tex]so \begin{gathered}2h(l+b)= C.S.A. \\\\\Rightarrow 2\times 4\times (2b+b)=150\\\\\Rightarrow 8\times 3b= 150\\\\\Rightarrow b= \dfrac{150}{8\times 3} = 6.25cm\end{gathered} [/tex]

   • => 2h(l+b) = C.S.A.

   • ⇒2×4×(2b+b)=150

   • ⇒8×3b=150

   • ⇒b = 8 × 3/150

   • =6.25cm

   [tex]\\ [/tex]

   length , l = 2b = 2 x 6.25 = 12.50 cm

   Area of Floor = l x b= 6.25 x 12.50 = 78.125 cm²

   Hence, area of the floor is 78.125 cm²

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   hope it helps : )

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