The Angles pf ∆PQR are In the ratio 1 : 2 : 3. Find all the Angles of the triangle.​

2 thoughts on “The Angles pf ∆PQR are In the ratio 1 : 2 : 3. Find all the Angles of the triangle.​”

1. [tex] \: \huge\colorbox{pink}{Question}[/tex]

   The Angles pf ∆PQR are In the ratio 1 : 2 : 3. Find all the Angles of the triangle.

   [tex] \: \huge\colorbox{pink}{Answer}[/tex]

   Let the angle of ∆PQR be x, 2x and 3x

   Since, sum of the angle of a triangle is 180°

   [tex] ∴ \: \: \: \: \: \: \: x + 2x + 3x = 180°[/tex]

   [tex] \: ⇒ \: \: \: \: \: \: \: \: \: \: \: 6x = 180°[/tex]

   [tex] \: ⇒ \: \: \: \: \: \: \: \: \: \: \: x = 30°[/tex]

   Also,

   [tex] \: \: \: \: \: \: 2x = 30°[/tex]

   And

   [tex] \: \: \ \: \: \: 3x = 90°[/tex]

   Hence, the Angles of ∆PQR are 30°,60° and 90°

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2. Answer:

   sum of angles of a triangle is always 180°.

   Let’s take the angles to be 1x : 2x : 3x.

   1x + 2x + 3x = 180°

   6x = 180°

   x = 180

   6

   x = 30

   1x = 30°

   2x = 30 × 2 = 60°

   3x = 30 × 3 = 90°

   PLEASE MARK AS BRAINLIEST.

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