The angles of a quadrilateral are (x). (x – 10), (x + 30) and (2x), find the smallest
angle​

2 thoughts on “The angles of a quadrilateral are (x). (x – 10), (x + 30) and (2x), find the smallest<br />angle​”

1. Answer:

   smallest angle be 68 degree

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2. [tex]\huge{\underline{\underline{\bf{\purple{answer}}}}}[/tex]

   [tex] \angle a + \angle b + \angle c + \angle d = 360 \\ \\ x + x – 10 + x + 30 + 2x = 360 \\ \\ 5x = 360 – 30 \\ \\ 5x = 330 \\ \\ x = \frac{330}{5} = 66 \\ \\ [/tex]

   x = 66°

   x – 10 = 66 – 10 = 56°

   x + 30 = 66 + 30 = 96°

   2x = 2 × 66 = 132°

   SMALLEST ANGLE IS ( X – 10 ) i.e 56°

   ☆BE BRAINLY☆

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