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If the curved surface area of a right circular cylinder whose base radius and heigh

2 thoughts on “<br />[tex] \\ \\ \\ \\ \\ \\ [/tex]<br />If the curved surface area of a right circular cylinder whose base radius and heigh”

1. [tex]\huge{\underline{\underline{\boxed{\mathscr{\red{Aɴsᴡᴇʀ\: ࿐}}}}}} [/tex]

   Solution :-

   We know,

   Curved surface area of cylinder = 2πrh

   [Where, r is radius and h is height of cylinder]

   Put all values :

   [tex]\longrightarrow 72π = 2 × π × r × h[/tex]

   Radius and height are equal.

   [tex]\longrightarrow 72π = 2π × r × r[/tex]

   [tex]\longrightarrow 72π = 2π × r²[/tex]

   [tex]\sf \longrightarrow \dfrac{72 \: \cancel{\pi}}{2 \: \cancel{\pi}}[/tex]

   [tex]\longrightarrow 36 = r²[/tex]

   [tex]\longrightarrow √36 = r[/tex]

   [tex]\longrightarrow \: r = 6[/tex]

   Radius of cylinder is 6 cm.

   Now,

   • Diameter = 2 × radius

   [tex]⟶ Diameter = 2 × 6[/tex]

   [tex]\longrightarrow \: Diameter = 12[/tex]

   Therefore,

   • Diameter of base of cylinder is 12 cm.

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2. [tex]\huge \sf \bf {\boxed{\underline {\pink{\underline {✠Aɴʂᴡᴇʀ࿐ :−}}}}} [/tex]

   Radius of cylinder (r)=7cm

   Height of cylinder (h)=15cm

   Curved Surface Area =2πrh

   =2×(22/7)×7×15

   =660cm

   2

   Total Surface Area =2πr(h+r)

   =2×(22/7)×7(15+7)

   =2×22×22

   =968cm

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