The question is subtract -1/2 from 4/5. By question, we need to take the second fraction in the front so as to get the correct answer. So now we get, 4/5 – (-1/2). As we know negative (-) × negative (-) = positive (+), so now we get,, 4/5 + 1/2. LCM of both the denominators 5 and 2 is 10, so now we multiply the numerators by the numbers we need to multiply the denominators so as to get 10= 4×2/5×2 + 1×5/2×5. 4×2= 8 & 1×5= 5, so now we get, 8+5/10. And finally we get the correct answer which is 8+5/10= 13/10.
[tex]Question:[/tex]
Subtract:
[tex] \frac{ – 1}{2} \: from \: \frac{4}{5} [/tex]
[tex]Answer:[/tex]
[tex] \frac{13}{10} [/tex]
[tex]How \: to \: get \: it:[/tex]
[tex] = > \frac{4}{5} – ( \frac{ – 1}{2} )[/tex]
[tex] = > \frac{4}{5} + \frac{1}{2} [/tex]
[tex] = > \frac{4 \times 2 + 1 \times 5}{10} [/tex]
[tex] = > \frac{8 + 5}{10} [/tex]
[tex] = > \frac{13}{10} [/tex]
[tex]Explanation:[/tex]
The question is subtract -1/2 from 4/5. By question, we need to take the second fraction in the front so as to get the correct answer. So now we get, 4/5 – (-1/2). As we know negative (-) × negative (-) = positive (+), so now we get,, 4/5 + 1/2. LCM of both the denominators 5 and 2 is 10, so now we multiply the numerators by the numbers we need to multiply the denominators so as to get 10= 4×2/5×2 + 1×5/2×5. 4×2= 8 & 1×5= 5, so now we get, 8+5/10. And finally we get the correct answer which is 8+5/10= 13/10.
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Answer :
[tex] \sf \frac{4}{5} – \frac{ – 1}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \frac{(4 \times 2) – ( – 1 \times 5)}{10} \: \: \: \: \: \: \tt{(LCM = 10)} \\ \\ \sf \implies \frac{8 – ( – 5)}{10} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \frac{8 + 5}{10} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \boxed {\red{ \sf{ \pmb{\frac{13}{10}}}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]