[tex]\sf {Find\:the\;mean\:of\:the\:Given\:data\:using\: any\:method}[/tex]
[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c|c|c|c|c}\bf {Class\:interval:-} &\sf 10-10 &\sf 20-29 &\sf 30-39 &\sf 40-49 &\sf 50-59 &\sf 60-69 &\sf 70-79 \\&&&&&&&\\ \bf {Frequency:-} &\sf 5 &\sf 65 &\sf 222 &\sf 112 &\sf 53 &\sf 40 &\sf 3 \end {array}}\end{gathered}[/tex]
Construct a frequency table for your answer.
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Answer:
Find\:the\;mean\:of\:the\:Given\:data\:using\: any\:method}[/tex]
[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c|c|c|c|c}\bf {Class\:interval:-} &\sf 10-10 &\sf 20-29 &\sf 30-39 &\sf 40-49 &\sf 50-59 &\sf 60-69 &\sf 70-79 \\&&&&&&&\\ \bf {Frequency:-} &\sf 5 &\sf 65 &\sf 222 &\sf 112 &\sf 53 &\sf 40 &\sf 3 \end {array}}\end{gathered}[/tex]
Construct a frequency table for your answer.
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To Find:-
Solution:–
As we know that:–
Here ,
[tex]\longrightarrow\sf \: Mean = \cancel\dfrac { 19500 } { 500 } [/tex]
[tex]\longrightarrow\sf \: Mean = 39 [/tex]
Hence ,