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[tex] \frac{1}{3x + y} + \frac{1}{3x – y} = \frac{3}{4} and \frac{1}{2(3x + y)} – \frac{1}{2(3x – y)} = – \frac{1}{

By Ella

[tex] \frac{1}{3x + y} + \frac{1}{3x – y} = \frac{3}{4} and \frac{1}{2(3x + y)} – \frac{1}{2(3x – y)} = – \frac{1}{8} [/tex]​

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Ella

The factors of 6×2 – 25x – 14 are
(A) (3x – 2) (2x + 7)
(B) (3x + 2) (2x – 7)
(C) (3x – 14) (2x + 1)
(D) (3x +

Theorem-If a and b are two positive real numbers such that ab is not a perfect square of a rational number, then √ab is an irratio

1 thought on “<br />[tex] \frac{1}{3x + y} + \frac{1}{3x – y} = \frac{3}{4} and \frac{1}{2(3x + y)} – \frac{1}{2(3x – y)} = – \frac{1}{”

  1. Answer:

    Multiply first equation with 1/2 and add it with second equation we get,

    1/(3x+y)=1/4

    Similarly we get,

    1/(3x-y)=1/2

    we get,

    3x=4-y,

    4-2y=2

    y=1,x=1

    Please mark my answer as BRAINLIEST answer

    hope you have a good day

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