[tex]4 \frac{1}{10} – 2 \frac{1}{3} + 3 \frac{2}{5} \\ \\ \frac{41}{10} – \frac{7}{3} + \frac{17}{5} \\ \\ \frac{123 – 70 + 102}{30} \\ \\ \frac{53 + 102}{30} \\ \\ \frac{155}{30} \\ \\ = 5.16[/tex] Reply
[tex]4 \frac{1}{10} – 2 \frac{1}{3} + 3 \frac{2}{5} \\ \\ \frac{41}{10} – \frac{7}{3} + \frac{17}{5} \\ \\ \frac{123 – 70 + 102}{30} \\ \\ \frac{53 + 102}{30} \\ \\ \frac{155}{30} \\ \\ = 5.16[/tex]