sum of the zeros of the polynomial p (x) = x square – kx + 9 is 7. Find the value of k. About the author Audrey
Let’s solve for K. [tex]px=x^2kx+9is(7)[/tex] Step 1: Flip the equation. [tex]kx^3+63-is=px[/tex] Step 2: Add -kx^3 to both sides. [tex]kx^3+63is+−kx^3=px+−kx^3[/tex] [tex]63-is=−kx^3+px[/tex] Step 3: Divide both sides by 63s. [tex]63-is-63s=−kx^3+px 63s[/tex] [tex]i=−kx^3+px 63s[/tex] Answer: [tex]→K=−kx^3+px 63s[/tex] Reply
Let’s solve for K.
[tex]px=x^2kx+9is(7)[/tex]
Step 1: Flip the equation.
[tex]kx^3+63-is=px[/tex]
Step 2: Add -kx^3 to both sides.
[tex]kx^3+63is+−kx^3=px+−kx^3[/tex]
[tex]63-is=−kx^3+px[/tex]
Step 3: Divide both sides by 63s.
[tex]63-is-63s=−kx^3+px 63s[/tex]
[tex]i=−kx^3+px 63s[/tex]
Answer:
[tex]→K=−kx^3+px 63s[/tex]