sum of the areas of two squares is 468 metres square if the difference of their perimeter is 24m find the sides of the squares by the quadratic equation of one variable About the author Ximena
Answer: From equation (1) and (2) , we get ∵ x² + ( x – 6 )² = 468 . ⇒ x² + x² – 12x + 36 = 468 . ⇒ 2x² – 12x + 36 – 468 = 0 . Step-by-step explanation: hope it’s helpful to you! Reply
Answer:
From equation (1) and (2) , we get
∵ x² + ( x – 6 )² = 468 . ⇒ x² + x² – 12x + 36 = 468 . ⇒ 2x² – 12x + 36 – 468 = 0 .
Step-by-step explanation:
hope it’s helpful to you!