It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a). So, First we will do the sum of the three given polynomials, Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a) =(a+4a−a)+(3b−b−2b)+(−4c+9c+3c) =4a+8c Now, we can perform the subtraction, Required difference =(4a+8c)−(2a−3b+4c) =4a+8c−2a+3b−4c =2a+3b+4c Hope it helps ❤️ Hi ^_^ I am Divi Reply
Step-by-step explanation: (3a – 2b + 4c) + (3b – 2c) – (a – b – c) = 3a – 2b + 4c + 3b – 2c – a + b + c = 2a + 2b + 3c Reply
It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
So, First we will do the sum of the three given polynomials,
Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
Now, we can perform the subtraction, Required difference
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
Hope it helps ❤️
Hi ^_^
I am Divi
Step-by-step explanation:
(3a – 2b + 4c) + (3b – 2c) – (a – b – c)
= 3a – 2b + 4c + 3b – 2c – a + b + c
= 2a + 2b + 3c