steps of construcbon. use ruler and| If angles of a triangle are in the ratio 1:2 3. Find the value of each angle,Arrange the following numbers in ascending order About the author Alaia
Answer: Let the angles of a triangle be x, 2x, 3x. angles of a triangle be x, 2x, 3x.Then, angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180° angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180° angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180° angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°x = 30° angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°x = 30° So, angles of a triangle = 30°, 60°, 90° angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°x = 30° So, angles of a triangle = 30°, 60°, 90° Reply
Answer:
Let the angles of a triangle be x, 2x, 3x.
angles of a triangle be x, 2x, 3x.Then,
angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°
angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°
angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°
angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°x = 30°
angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°x = 30° So, angles of a triangle = 30°, 60°, 90°
angles of a triangle be x, 2x, 3x.Then, Sum of angles = 180°x +2x + 3x =180°6x = 180°x = 30° So, angles of a triangle = 30°, 60°, 90°