1 thought on “state true or false If (x – a) (x – b) < 0, then x < a, and x < b.”
Step-by-step explanation:
[tex]\blue{\mathfrak{\underline{\large{It’s\:true.}}}} \\ (x-a)(x-b)<0\\\blue{\mathfrak{\underline{\large{Solving\: inequality}}}:} \\ \\ \frac{(x-a)(x-b)}{(x – b)} < \frac{0}{(x – b)} \\ x – a < 0 \\ x – a + a < 0 + a \\ x < a \\ \\\frac{(x-a)(x-b)}{(x – a)} < \frac{0}{(x – a)} \\ x – b< 0 \\ x – b + b < 0 + b \\ x < b \\ \red{\mathfrak{\underline{\large{Hope\:it\:helps\:you}}}} \\\blue{\mathfrak{\underline{\large{Mark\:me\: Brainliest}}}}\\
Step-by-step explanation:
[tex]\blue{\mathfrak{\underline{\large{It’s\:true.}}}} \\ (x-a)(x-b)<0\\\blue{\mathfrak{\underline{\large{Solving\: inequality}}}:} \\ \\ \frac{(x-a)(x-b)}{(x – b)} < \frac{0}{(x – b)} \\ x – a < 0 \\ x – a + a < 0 + a \\ x < a \\ \\\frac{(x-a)(x-b)}{(x – a)} < \frac{0}{(x – a)} \\ x – b< 0 \\ x – b + b < 0 + b \\ x < b \\ \red{\mathfrak{\underline{\large{Hope\:it\:helps\:you}}}} \\\blue{\mathfrak{\underline{\large{Mark\:me\: Brainliest}}}}\\
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