solve the quadratic equation x2 + 3x = 10 by factorization method​

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1. Answer:

   Question :–

   solve the quadratic equation x2 + 3x = 10 by factorization method.

   Solution :–

   let’s first arrange the given quadratic polynomial in standard form ax² + bx + c

   [tex] {x}^{2} + 3x – 10 = 0[/tex]

   Now let’s factorise by splitting the middle term in such a way that some should be 3x and multiplication should be minus 10

   [tex] {x}^{2} – 2x + 5x – 10[/tex]

   [tex] = x(x – 2) – 5(x – 2)[/tex]

   [tex] = (x – 5)(x – 2)[/tex]

   Finding zeroes :–

   i ) x – 5 = 0⠀⠀⠀⠀⠀⠀⠀ii ) x – 2 = 0 ⠀⠀⠀

   x = 5⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀x = 2

   So, the value of x²+3x-10 is zero when x – 5 = 0 or x – 2, i.e., when x = +5 or x = +2 therefore the zeroes of x²+ 3x- 10 are five and ten.

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