Given Equation ⇒2x – y = 5 (i) ⇒2x + y = -1 (ii) Now Take ⇒2x – y = 5 (i) When x = 0 ⇒2(0) – y = 5 ⇒y = -5 We get point (0 , -5) When y = 0 ⇒2x – 0 = 5 ⇒2x = 5 ⇒x = 5/2 We get point (5/2 , 0 ) Now Take ⇒2x + y = -1 (ii) When x = 0 ⇒2(0) + y = -1 ⇒y = -1 We get point (0 , -1) When y = 0 ⇒2x + 0 = -1 ⇒2x = -1 ⇒x = -1/2 We get point (-1/2 , 0) Reply
Answer: x=1 y=-3 Step-by-step explanation: 2x-y=5 eq1 2x+y=-1 eq2 From eq 1 and 2, add them, we get, 2x-y=5 2x+y=-1 4x=4 x=1 From 1,we get, 2*1-y=5 -y=3 y=-3 Reply
Given Equation
⇒2x – y = 5 (i)
⇒2x + y = -1 (ii)
Now Take
⇒2x – y = 5 (i)
When x = 0
⇒2(0) – y = 5
⇒y = -5
We get point (0 , -5)
When y = 0
⇒2x – 0 = 5
⇒2x = 5
⇒x = 5/2
We get point (5/2 , 0 )
Now Take
⇒2x + y = -1 (ii)
When x = 0
⇒2(0) + y = -1
⇒y = -1
We get point (0 , -1)
When y = 0
⇒2x + 0 = -1
⇒2x = -1
⇒x = -1/2
We get point (-1/2 , 0)
Answer:
x=1 y=-3
Step-by-step explanation:
2x-y=5 eq1
2x+y=-1 eq2
From eq 1 and 2, add them, we get,
2x-y=5
2x+y=-1
4x=4
x=1
From 1,we get,
2*1-y=5
-y=3
y=-3