Given : 3x² – 14x + 8 = 0 ━━━━━━━━━━━━━━━━━━ ➳ 3x² – 14x + 8 = 0 ➳ 3x² – 12x – 2x + 8 = 0 ➳ 3x (x – 4) – 2 (x – 4) = 0 ➳ (x – 4) (3x – 2) = 0 (Factorising left side) ➳ x – 4 = 0 or 3x – 2 = 0 (Zero – product rule) ➳ x = 4 or x = 2/ 3 ━━━━━━━━━━━━━━━━━━ ❶ When x ∈ N : ➢ As 4 ∈ N and 2/3 ∉ N, ☆ Therefore, The given equation has 4 as its roots. ❷ When x ∈ Q : ➢ As 4, 2/3 ∈ Q, ☆ Therefore, The given equation has 4, 2/3 as its roots. ━━━━━━━━━━━━━━━━━━ Reply
Solution:– => 3x²-14x+8=0 => 3x²-12x-2x+8=0 => 3x(x-4)-2(x-4)=0 => (3x-2)(x-4)=0 => x=2/3 and x=4 => When x ∈ N As 4 ∈N and 2/3 not belongs to N Therefore The equation has 4 as it’s root. => When x ∈ Q As 4,2/3 ∈ Q Therefore The equation has 4, 2/3 as it’s roots. Reply
Given : 3x² – 14x + 8 = 0
━━━━━━━━━━━━━━━━━━
➳ 3x² – 14x + 8 = 0
➳ 3x² – 12x – 2x + 8 = 0
➳ 3x (x – 4) – 2 (x – 4) = 0
➳ (x – 4) (3x – 2) = 0 (Factorising left side)
➳ x – 4 = 0 or 3x – 2 = 0 (Zero – product rule)
➳ x = 4 or x = 2/ 3
━━━━━━━━━━━━━━━━━━
❶ When x ∈ N :
➢ As 4 ∈ N and 2/3 ∉ N,
☆ Therefore,
❷ When x ∈ Q :
➢ As 4, 2/3 ∈ Q,
☆ Therefore,
━━━━━━━━━━━━━━━━━━
Solution:–
=> 3x²-14x+8=0
=> 3x²-12x-2x+8=0
=> 3x(x-4)-2(x-4)=0
=> (3x-2)(x-4)=0
=> x=2/3 and x=4
=> When x ∈ N
As 4 ∈N and 2/3 not belongs to N
Therefore
=> When x ∈ Q
As 4,2/3 ∈ Q
Therefore