Solve quadratic equations using formula
y²-2y=-3=0​

2 thoughts on “<br />Solve quadratic equations using formula<br />y²-2y=-3=0​”

1. Answer:

   Solution: y=1+√5;y=1-√5

   Step-by-step explanation:

   y²-2y-3=0

   a=1, b=-2,c=-3

   b²-4ac

   =-2²-4×-2×-3

   =4-(-16)

   =4+16

   =20

   Using quadratic formula

   y={-b±√(b²-4ac)}/2a

   y={-(-2)±√20}/2×1

   y=(2±√20)/2

   y=(2+√20)/2 ; y=(2-√20)/2

   y=(2+2√5)/2 ; y=(2-2√5)/2

   y=2(1+√5)/2 ; y=2(1-√5)/2

   y=1+√5 ; y=1-√5

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2. Answer:

   Step 1 :Trying to factor by splitting the middle term. 1.1 Factoring y2-2y+3. The first term is, y2 its coefficient is 1 . The middle term is, -2y its coefficient is -2 . …

   Step 2 : Parabola, Finding the Vertex: 2.1 Find the Vertex of t = y2-2y+3.

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