Answer: Ok good question Step-by-step explanation: [tex] \frac{7 + x}{(1 + x)(1 + { x}^{2) } } = \frac{a}{1 + x} + \frac{bx + c}{1 + {x}^{2} } \\ = 7 + x = a \: (1 + {x}^{2} ) + (bx + c) \: (1 + x) \\ 7 + x = a (1 + {x}^{2} ) + b \: x + {x}^{2} + c \: (1 + x) \: [/tex] Reply
Answer:
Ok good question
Step-by-step explanation:
[tex] \frac{7 + x}{(1 + x)(1 + { x}^{2) } } = \frac{a}{1 + x} + \frac{bx + c}{1 + {x}^{2} } \\ = 7 + x = a \: (1 + {x}^{2} ) + (bx + c) \: (1 + x) \\ 7 + x = a (1 + {x}^{2} ) + b \: x + {x}^{2} + c \: (1 + x) \: [/tex]