sinx=3/5x lies in the second quadrant. Find the values of cosx and tanx​

1 thought on “sinx=3/5x lies in the second quadrant. Find the values of cosx and tanx​”

1. Answer:

   cosx=√cos^2x=√(1-sin^2x=+4/6/5 or -4/5

   since it is in second quadrant it is -4/5

   similarly tanx=-3/4

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