Contact Style About

[(sin^2 theta÷2) – ( cos^2 theta÷ 2)] ÷ (sin theta÷2 cos theta÷2) = 1 – (1÷2 sin theta)​

By Madeline

[(sin^2 theta÷2) – ( cos^2 theta÷ 2)] ÷ (sin theta÷2 cos theta÷2) = 1 – (1÷2 sin theta)​

About the author
Madeline




If in a triangle ABC
COS A
cos B cos C

a b
2 – + + 2-
+
b
с
then t

The sum of x^2-y^2,y^2-z^2 and z^2-x^2 is
a.1
b.-1
c.0
d.2
Please tell the correct answer, i will ma

1 thought on “[(sin^2 theta÷2) – ( cos^2 theta÷ 2)] ÷ (sin theta÷2 cos theta÷2) = 1 – (1÷2 sin theta)​”

Leave a Comment