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show that
cosx + sin(270°+x) -sin(270-x) + cos(180°+x) =0​

By Lydia

show that
cosx + sin(270°+x) -sin(270-x) + cos(180°+x) =0​

About the author
Lydia

‘Never trust your fears as they don’t know your strength’. Detail the statement in context with
‘Deep Water​

PLS ANSWER QUICKLY
[tex]6/3[tex]\sqrt{2} +2\sqrt{3}[/tex][/tex]

1 thought on “show that<br />cosx + sin(270°+x) -sin(270-x) + cos(180°+x) =0​”

  1. Answer:

    The explanation has been given on step-by-step explanation.

    Step-by-step explanation:

    cosx + sin (270°+x) – sin (270°-x) + cos (180°+x)

    = cosx + sin (3π+x) – sin (3π-x) + cos (2π+x)

    = cosx – sinx + sinx – cosx

    = 0

    So, L.H.S = R.H.S

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