Show AnswerQuestion #4If the absolute difference between the selling price of the article when there is 15% loss and 15% gain inselling a article is Rs 450, then what is the cost price of the article?Y Rs 1,200Rs 1,500Rs 2.000Rs 2 200 About the author Kinsley
Answer: The cost price of the article is 1,500. Step-by-step explanation: Here, as per the provided information in the given question, we have : • Difference between the selling price of the article when there is 15% loss and 15% gain in selling a article is Rs 450. We are asked to calculate the cost price of the article. Let us assume the cost price of article as Rs. x. ⇒ Cost price = Rs. x ★ Calculating SP when there is 15% loss :- [tex] \longrightarrow \underline{ \boxed {\sf { S.P = \Bigg ( \dfrac{100-Loss \%}{100} \Bigg ) \times C.P}} }\\ [/tex] C.P (Cost price) = x Loss % = 15 % Substituting the given values. [tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{100-15}{100} \Bigg ) \times x }\\ [/tex] [tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{85}{100} \Bigg ) \times x }\\ [/tex] [tex] \longrightarrow \sf {S.P = \dfrac{85}{100} x }\\ [/tex] Let it be the equation (1). ★ Calculating SP when there is 15% gain :– [tex] \longrightarrow \underline{ \boxed {\sf { S.P = \Bigg ( \dfrac{100+ Gain \%}{100} \Bigg ) \times C.P}} }\\ [/tex] C.P (Cost price) = x Gain % = 15 % Substituting the given values. [tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{100+15}{100} \Bigg ) \times x }\\ [/tex] [tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{115}{100} \Bigg ) \times x }\\ [/tex] [tex] \longrightarrow \sf {S.P = \dfrac{115}{100} x }\\ [/tex] Let it be the equation (2). ★ According to the question, [tex] \longrightarrow [/tex] Selling price when there is 15% gain ― Selling price when there is 15% loss = Rs. 450 [tex] \longrightarrow \sf { \dfrac{115}{100}x – \dfrac{85}{100}x = Rs. \: 450 }\\ [/tex] [tex] \longrightarrow \sf { \dfrac{115x – 85 x}{100} = Rs. \: 450 }\\ [/tex] [tex] \longrightarrow \sf { \dfrac{30x}{100} = Rs. \: 450 }\\ [/tex] [tex] \longrightarrow \sf { \dfrac{3x}{10} = Rs. \: 450 }\\ [/tex] [tex] \longrightarrow \sf { 3x = Rs. \: (450 \times 10) }\\ [/tex] [tex] \longrightarrow \sf { 3x = Rs. \: 4500 }\\ [/tex] [tex] \longrightarrow \sf { x = Rs. \: \cancel{\dfrac{4500}{3} }}\\ [/tex] [tex] \longrightarrow \sf { x = Rs. \: 1500 }\\ [/tex] [tex] \longrightarrow\underline{\boxed{ \sf { C.P = Rs. \: 1500 }}} \; \bigstar\\ [/tex] Therefore, cost price of the article is Rs. 1500. _____________________ ★ Some related formulae : Gain = S.P – C.P Loss = C.P – S.P ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ [tex] \rm { Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} [/tex] ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ [tex] \rm { Loss \: \% = \Bigg( \dfrac{Loss}{C.P} \times 100 \Bigg)\%} [/tex] ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ [tex] \rm { S.P = \dfrac{100+Gain\%}{100} \times C.P} [/tex] ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ [tex] \rm { C.P =\dfrac{100}{100+Gain\%} \times S.P} [/tex] ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ [tex] \rm { S.P = \dfrac{100-loss\%}{100} \times C.P} [/tex] ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ [tex] \rm { C.P =\dfrac{100}{100-loss\%} \times S.P} [/tex] Reply
Answer:
The cost price of the article is 1,500.
Step-by-step explanation:
Here, as per the provided information in the given question, we have :
• Difference between the selling price of the article when there is 15% loss and 15% gain in selling a article is Rs 450.
We are asked to calculate the cost price of the article.
Let us assume the cost price of article as Rs. x.
⇒ Cost price = Rs. x
★ Calculating SP when there is 15% loss :-
[tex] \longrightarrow \underline{ \boxed {\sf { S.P = \Bigg ( \dfrac{100-Loss \%}{100} \Bigg ) \times C.P}} }\\ [/tex]
Substituting the given values.
[tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{100-15}{100} \Bigg ) \times x }\\ [/tex]
[tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{85}{100} \Bigg ) \times x }\\ [/tex]
[tex] \longrightarrow \sf {S.P = \dfrac{85}{100} x }\\ [/tex]
Let it be the equation (1).
★ Calculating SP when there is 15% gain :–
[tex] \longrightarrow \underline{ \boxed {\sf { S.P = \Bigg ( \dfrac{100+ Gain \%}{100} \Bigg ) \times C.P}} }\\ [/tex]
Substituting the given values.
[tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{100+15}{100} \Bigg ) \times x }\\ [/tex]
[tex] \longrightarrow \sf {S.P = \Bigg ( \dfrac{115}{100} \Bigg ) \times x }\\ [/tex]
[tex] \longrightarrow \sf {S.P = \dfrac{115}{100} x }\\ [/tex]
Let it be the equation (2).
★ According to the question,
[tex] \longrightarrow [/tex] Selling price when there is 15% gain ― Selling price when there is 15% loss = Rs. 450
[tex] \longrightarrow \sf { \dfrac{115}{100}x – \dfrac{85}{100}x = Rs. \: 450 }\\ [/tex]
[tex] \longrightarrow \sf { \dfrac{115x – 85 x}{100} = Rs. \: 450 }\\ [/tex]
[tex] \longrightarrow \sf { \dfrac{30x}{100} = Rs. \: 450 }\\ [/tex]
[tex] \longrightarrow \sf { \dfrac{3x}{10} = Rs. \: 450 }\\ [/tex]
[tex] \longrightarrow \sf { 3x = Rs. \: (450 \times 10) }\\ [/tex]
[tex] \longrightarrow \sf { 3x = Rs. \: 4500 }\\ [/tex]
[tex] \longrightarrow \sf { x = Rs. \: \cancel{\dfrac{4500}{3} }}\\ [/tex]
[tex] \longrightarrow \sf { x = Rs. \: 1500 }\\ [/tex]
[tex] \longrightarrow\underline{\boxed{ \sf { C.P = Rs. \: 1500 }}} \; \bigstar\\ [/tex]
Therefore, cost price of the article is Rs. 1500.
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★ Some related formulae :
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