Rupees 18210 is invested in three schemes. A, B and C for 5 years, 8 years and 4 years respectively. If these three schemes give a simple interest of 12%, 10% and 12.5% respectively. After completion of each scheme a person gets6 amount in the ratio 3:7:4 from these schemes. Then find the sum of money invested in scheme C?
A. Rs. 4320
B. Rs. 5760
C. Rs. 5880
D. Rs. 5120
Given : Rupees 18210 is invested in three schemes. A, B and C for 5 years, 8 years and 4 years respectively. If these three schemes give a simple interest of 12%, 10% and 12.5% respectively. After completion of each scheme a person gets amount in the ratio 3:7:4 from these schemes.
To Find : the sum of money invested in scheme C?
Solution:
Amount invested in B = 100B
Amount invested in C = 100C
Amount invested in A = 18210 – 100B – 100C
Amount received in A = (18210 – 100B – 100C) + (5* 12/100)( 18210 – 100B – 100C)
= (18210 – 100B – 100C) (1.6)
= (29,136 – 160B – 160C)
Amount received in B = 100B + ( 8 * 10/100)100B
= 180B
Amount received in C = 100C + ( 4 * 12.5/100)100C
= 150C
(29,136 – 160B – 160C) : 180B : 150C = 3 : 7 : 4
29,136 – 160B – 160C = 3K
180B = 7k
150C = 4k
=> 180B/150C = 7/4
=> 6B/5C = 7/4
=> 24B = 35C
3k + 4k = 7k
29,136 – 160B – 160C + 150C = 180B
=> 29,136 = 340B + 10C
=> 29,136 = 340(35C/24) + 10C
=> 29,136 * 24 = 12,140C
=> C = 57.6
=> 100C = 5760
the sum of money invested in scheme C = 5760 Rs
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Given :– Rupees 18210 is invested in three schemes. A, B and C for 5 years, 8 years and 4 years respectively. If these three schemes give a simple interest of 12%, 10% and 12.5% respectively. After completion of each scheme a person gets amount in the ratio 3:7:4 from these schemes. Then find the sum of money invested in scheme C ?
A. Rs. 4320
B. Rs. 5760
C. Rs. 5880
D. Rs. 5120
Answer :–
→ A + B + C = 18210 ———- Eqn.(1)
Let Rs.A invested in scheme A , Rs. B in B and Rs.C in C .
so, amount ratio :-
→ [A + (A*12*5/100)] : [B + (B*10*8/100)] : [C + (C*12.5*4/100)] : 3 : 7 : 4
→ [A + (3A/5)] : [B + (4B/5)] : [C + (C/2)] = 3 : 7 : 4
→ (8A/5) : (9B/5) : (3C/2) = 3 : 7 : 4
Let,
then, we get,
→ A = (15k/8)
→ B = (35k/9)
→ C = (8k/3)
putting,
→ (15k/8) + (35k/9) + (8k/3) = 18210
→ (135k + 280k + 192k ) / 72 = 18210
→ 607k = 18210 * 72
→ k = (18210 * 72)/607
→ k = 2160
therefore,
→ C = (8k/3) = (8 * 2160)/3 = Rs.5760 (Ans.)
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